X++ code to fetch the fileName from Directory based on Current Company Code

Hi ,

Refer below code which will fetch the filename from Directory (FilePath) based on Current Company Code


 static container findMatchingFiles(
        str _folderPath
    ,   str _filePattern   = '.txt')
{
    System.IO.DirectoryInfo     directory;
    System.IO.FileInfo[]        files;
    System.IO.FileInfo          file;
    InteropPermission           permission;
    str         fileName;
    counter     filesCount;
    counter     loop;
    container   mathchingFiles;
    ;
    permission  = new InteropPermission(InteropKind::ClrInterop);
    permission.assert();
     //BP Deviation Documented
    directory   = new System.IO.DirectoryInfo(_folderPath);
    files       = directory.GetFiles(_filePattern);
    filesCount  = files.get_Length();
    for (loop = 0; loop < filesCount; loop++)
    {
        file            = files.GetValue(loop);
        fileName        = file.get_FullName();
        mathchingFiles  = conins(mathchingFiles, conlen(mathchingFiles) + 1, fileName);
    }
    CodeAccessPermission::revertAssert();
    return mathchingFiles;
}

static FileName fetchFiles(Args _args)
{
    container   files;
    counter     loop;
    FileName         fileName;
  
    str entityId;
   
    Filename filepathVal;
    Filename fileType;
    filename fileNameString;
    ;
    entityId=strLfix('E'+curext(),7,'0');
    files = DNT_DatabasicsUpload::findMatchingFiles(#FilePath, entityId+'*.txt');
    for (loop = 1; loop <= conlen(files); loop++)
    {
   
        filename= conpeek(files, loop);
        return filename;
      
    }
    return #FilePath;
}

Happy Daxing...............